Question

An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car that is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car’s velocity?

Answer 1

• initial velocity=15m/s=u
• Acceleration=a=5m/s^2
• Final velocity=v=30m/s
• Distance be s

Using 3rd equation of kinematics

`\\ \rm\longmapsto v^2-u^2=2as`

`\\ \rm\longmapsto s=(v^2-u^2)/(2a)`

`\\ \rm\longmapsto s=(30^2-15^2)/(2(5))`

`\\ \rm\longmapsto s=(900-225)/(10)`

`\\ \rm\longmapsto s=(675)/(10)`

`\\ \rm\longmapsto s=67.5m`