Question

I want to solve these mathematical equations

2t-✓2= 3t+✓2. Number 1
(-x+2✓3)(-3x-✓2) =0 number 2

Answer 1

which class you read now

Answer 2

see explanation

Explanation:

Given

2t -
`√(2)` = 3t +
`√(2)` ( add
`√(2)` to both sides )

2t = 3t + 2
`√(2)` ( subtract 3t from both sides )

- t = 2
`√(2)` ( multiply both sides by - 1 )

t = - 2
`√(2)`

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Given

(- x + 2
`√(3)` )(- 3x -
`√(2)` ) = 0

Equate each factor to zero and solve for x

- x + 2
`√(3)` = 0 ( subtract 2
`√(3)` from both sides )

- x = - 2
`√(3)` ( multiply both sides by - 1 )

x = 2
`√(3)`

- 3x -
`√(2)` = 0 ( add
`√(2)` to both sides )

- 3x =
`√(2)` ( divide both sides by - 3 )

x = -
`(√(2) )/(3)`