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35 votes
35 votes
2. A force of 20N acts on a particle of mass 2 Kg and displaces it by 5m at an angle 30°. What is the work done? a) 40J ) b) 50 J c) 100J​

User Corleone
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3.1k points

2 Answers

12 votes
12 votes

Mass is not required

  • Force=F=20N
  • Angle=30°
  • Displacement=s=5m


\\ \rm\longmapsto W=Fscos\Theta


\\ \rm\longmapsto W=20(5)cos30


\\ \rm\longmapsto W=100* (√(3))/(2)


\\ \rm\longmapsto W=50√(3)J

User Henrik Hansson
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3.0k points
15 votes
15 votes

Answer:


we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 * 5 * \cos(30) \\ 100 \cos(30) \\ = 100 ( √(3) )/(2) \\ = 50 √(3) \\ = 86.6 \: joule\\ thank \: yo

User Dijkstra
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3.3k points