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12ax² - (9a² - 8b²) x + (2a² + 5ab + 2b²) = 0 solve for x​

1 Answer

7 votes

Answer:


\sqrt{((8b^2-9a^2)^2)/(576a^2)-(2b^2+5ab+2a^2)/(12a) } -(8b^2-9a^2)/(24a) \\\\or\\-\sqrt{((8b^2-9a^2)^2)/(576a^2)-(2b^2+5ab+2a^2)/(12a) } -(8b^2-9a^2)/(24a)

Explanation:

The quadratic formula for


ax^2+bx+c=0

the solution is: (-b±√(b²-4ac))/(2a)

The solution is:


\sqrt{((8b^2-9a^2)^2)/(576a^2)-(2b^2+5ab+2a^2)/(12a) } -(8b^2-9a^2)/(24a) \\\\or\\-\sqrt{((8b^2-9a^2)^2)/(576a^2)-(2b^2+5ab+2a^2)/(12a) } -(8b^2-9a^2)/(24a)

User Maxdebayser
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