Final answer:
The mass of barium that participated in the chemical reaction is calculated by multiplying the number of moles of barium (0.070) by its molar mass (137.327 g/mol), resulting in a mass of 9.613 grams.
Step-by-step explanation:
To calculate the mass of barium that participated in the chemical reaction using the given 0.070 moles of barium, we need to use the molar mass of barium. The molar mass of barium (Ba) is approximately 137.327 g/mol. Using the formula:
Mass = moles × molar mass,
we get:
Mass = 0.070 moles × 137.327 g/mol = 9.613 g (rounded to three significant figures).
Therefore, the mass of barium that participated in the chemical reaction is 9.613 grams.