Question

In the following figure, a table of mass 0.44 Kg is pushed against an inclined surface with a 15 inclination angle. Find the amount of the horizontal component of the Weight

Answer 1

W = 1.11 N

Step-by-step explanation:

Given that,

Mass of a table, m = 0.44 kg

It is pushed against an inclined surface with a 15 inclination angle.

We need to find the amount of the horizontal component of the weight. The horizontal component of weight is given by :

`W=mg\sin\theta\\\\W=0.44* 9.8* \sin(15)\\\\W=1.11\ N`

So, the amount of the horizontal component of the weight is 1.11 N.