Question

A body to projected horizontally with a velocity of 100m/s

from the top of a tower 200m above the ground deduce
the following
time of flight and
Range obtained​

Answer 1

(a) Time flight is 6.39 s

(b) The range of the projectile is 639 m.

Step-by-step explanation:

Given;

initial horizontal velocity of the projectile,
`v_x` = 100 m/s

initial vertical velocity of the projectile,
`v_y` = 0

height of the tower, h = 200 m

(a) Time flight is calculated as follows;

`h = v_yt + (1)/(2) gt^2\\\\h = 0 + (1)/(2) gt^2\\\\h = (1)/(2) gt^2\\\\t = \sqrt{(2h)/(g) } \\\\t = \sqrt{(2* 200)/(9.8) }\\\\t = 6.39 \ s`

(b) The range of the projectile is calculated as follows;

`R = v_x * t\\\\R = 100\ m/s \ * \ 6.39\ s\\\\R = 639 \ m`