Question

How much heat is added if 0.5137g of water increases in temperature by 0.871 degrees C?

Answer 1

1.87 J

Step-by-step explanation:

q = c x m x (T2-T1)

c- specific heat of water (4.186 j/g.C)

q = 4.186 x 0.5137 x 0.871 = 1.87 J