Given:
Principal = ₹ 5000
Compound rate of interest = 6% per annum
Time = 3 years
To find:
The amount after 3 years of compound interest.
Solution:
Formula for amount is:
![A=P\left(1+(r)/(100)\right)^t](https://img.qammunity.org/2022/formulas/mathematics/high-school/jlqscp1kdh62oqp44kfmo3p9o26t4xdiyn.png)
Where, P is principal, r is rate of interest in % and t is the number of years.
Putting P=5000, r=6 and t=3, we get
![A=5000\left(1+(6)/(100)\right)^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/tyz3e9r0q86i0o1jp421nf3tybrfna0d4p.png)
![A=5000\left(1+0.06\right)^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/6pnwmi2v0x8frd65zxnci33tyx3rq611bx.png)
![A=5000\left(1.06\right)^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/4s6jwdmu4jcblctks7mj9r3ssc9klr8kg2.png)
On further simplification, we get
![A=5000(1.018108216)](https://img.qammunity.org/2022/formulas/mathematics/high-school/7giwftamvzfkvm1aqluzm67m36570ocs3f.png)
![A=5000(1.191016)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xdx8msdfax8196in458x4riz4rjifacizo.png)
![A=5955.08](https://img.qammunity.org/2022/formulas/mathematics/high-school/jxhrt55vftea3yunkpxinhcesjew3r6evr.png)
Therefore, the amount after 3 years of compound interest is 5955.08.