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Find the base of a triangle whose altitude is 12 cm and area is 96 cm

1 Answer

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Given:

Altitude of a triangle = 12 cm

Area of the triangle = 96 sq. cm

To find:

The base of the triangle.

Solution:

The area of a triangle is


Area=(1)/(2)* base* height

Putting Area = 96 and height = 12, we get


96=(1)/(2)* base* 12


96=6* base

Divide both sides by 6.


(96)/(6)=base


16=base

Therefore, the base of the triangle is 16 cm.

User Jdickel
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