Given:
Altitude of a triangle = 12 cm
Area of the triangle = 96 sq. cm
To find:
The base of the triangle.
Solution:
The area of a triangle is
![Area=(1)/(2)* base* height](https://img.qammunity.org/2022/formulas/mathematics/high-school/dg00k6k3o9wjc4fj90idlyq3kl3p8mv0jj.png)
Putting Area = 96 and height = 12, we get
![96=(1)/(2)* base* 12](https://img.qammunity.org/2022/formulas/mathematics/high-school/5xlqfh5g3n4fblnllgqbm91rg7gkrim7rq.png)
![96=6* base](https://img.qammunity.org/2022/formulas/mathematics/high-school/x07jfqrc08oyxk0q7diftssebw06k9u13n.png)
Divide both sides by 6.
![(96)/(6)=base](https://img.qammunity.org/2022/formulas/mathematics/high-school/jltbknhapzjwkjlxxay9eb9gluk2xrs97b.png)
![16=base](https://img.qammunity.org/2022/formulas/mathematics/high-school/fdbfkf1mv66dd4ywkx1xeiqmqf9gh97nss.png)
Therefore, the base of the triangle is 16 cm.