Find ef if e (1,-2) and f (7,6)

Laurent Farcy asked Mar 1, 2022

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Laurent Farcy asked Mar 1, 2022

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19 votes

y-y1=a(x-x1)
a=(y2-y1)/(x2-x1)
a= (6-(-2))/(7-1)
a=8/6
a=4/3
y-6=4/3(x-7)
y-6=4/3x-28/3
y=4/3x-28/3+6
y=4/3x-10/3 >>ef

Liu Kang answered Mar 8, 2022

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