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A 3.6 g sample of iron (III) oxide reacts with sufficient aluminum to be entirely used up.

How much iron is produced?

User WillZ
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1 Answer

5 votes

Answer:

0.046 mol

Step-by-step explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 2 Al ⇒ 2 Fe + Al₂O₃

Step 2: Calculate the moles corresponding to 3.6 g of Fe₂O₃

The molar mass of Fe₂O₃ is 159.69 g/mol.

3.6 g × 1 mol/159.69 g = 0.023 mol

Step 3: Calculate the moles of Fe produced from 0.023 moles of Fe₂O₃

The molar ratio of Fe₂O₃ to Fe is 1:2.

0.023 mol Fe₂O₃ × 2 mol Fe/1 mol Fe₂O₃ = 0.046 mol Fe

User GillyD
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