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Simplify and write the trigonometric expression in terms of sine and cosine:

(2+tan^2x/sec^2x) -1 =(f(x))^2​

1 Answer

10 votes

Answer:

f(x) = + cosx or - cosx

Explanation:

(2+tan^2x/sec^2x) -1 =(f(x))^2​

=(( 1 + sec^2x)/sec^2x) -1

= 1 / sec^2x + 1 - 1

= 1 / sec^2x

= cos^2x

(f(x))^2​ = cos^2x

f(x) = + cosx or - cosx

User Roy Clarkson
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