474,572 views
14 votes
14 votes
Can someone help me with this?​

Can someone help me with this?​-example-1
User CMerrill
by
3.1k points

2 Answers

10 votes
10 votes

Its a GP given by 2+6+18

  • First term=a=2

Common ratio=r=


\\ \bull\tt\looparrowright (6)/(2)=3

Now


\\ \bull\tt\looparrowright S_n=728


\\ \bull\tt\looparrowright (a(r^n-1))/(r-1)=728


\\ \bull\tt\looparrowright (2(3^n-1))/(3-1)=728


\\ \bull\tt\looparrowright (2(3^n-1))/(2)=728

  • Cancel 2


\\ \bull\tt\looparrowright 3^n-1=728


\\ \bull\tt\looparrowright 3^n=728+1


\\ \bull\tt\looparrowright 3^n=729


\\ \bull\tt\looparrowright 3^n=3^6


\\ \bull\tt\looparrowright n=6

User Shlomi Schwartz
by
3.0k points
10 votes
10 votes

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,


Sum = \frac{a( {r}^(n) - 1) }{(r - 1)} \\

So,


\frac{a( {r}^(n) - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^(n) - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^(n) - 1) }{2} = 728 \\ {3}^(n) - 1 = 728 \\ {3}^(n)=728+1\\ {3}^(n) = 729 \\ {3}^(n) = {3}^(6) \\ \boxed{ n = 6}

Therefore, number of terms is 6

  • 6 is the right answer.
User Miz
by
3.3k points
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