Question

a body starts moving from rest and attains the acceleration of 2 metre square calculate the velocity at the end of 310 minutes and also find the distance traveled by it during that time​

Answer 1

Here, we have

Initial velocity, u = 0 m/s (As starts from rest)

Acceleration, a = 2 m/s².

Time taken, t= 310 min = 310 × 60 = 18600 seconds

To Find,

Final velocity, v and,

Distance covered, s

Formula to be used,

1st and 3rd equation of motion,

v = u + at and v² - u² = 2as

So, putting all the values, we get

V = u + at

v = 0 + 2 x 18600

v = 2 x 18600 → v = 37200 m/s.

Hence, the final velocity is 37200 m/s.

Now, Distance covered,

v² - u²= 2as

(37200 )² - (0)² = 2 x 2 x s

1,383,840,000 = 4s → s = 345,960,000m

Hence, the distance covered is 345,960,000 m.