Answer:
Option (3)
Explanation:
Value of a car with a depreciation rate 'r' after time 't' is given by the formula,
v(t) =
![v_0(1-(r)/(100))^t](https://img.qammunity.org/2022/formulas/mathematics/high-school/uymnix1du98r84wkmamoz3hus7po9lp8fc.png)
Here, v(t) = Final value
= Initial value
r = rate of depreciation
From the given function,
v(t) =
![24893(0.88)^t](https://img.qammunity.org/2022/formulas/mathematics/high-school/mo96gega4dqrer1ttdjj722z3chvib1tl5.png)
v(t) =
![24893(1-0.12)^t](https://img.qammunity.org/2022/formulas/mathematics/high-school/do6ddbdr4giqi0liu0utrgi0hi3om1satq.png)
=
![24893(1-(12)/(100))^t](https://img.qammunity.org/2022/formulas/mathematics/high-school/ynp0807r8r5u6lt7r3pxn5h8unb8u12skj.png)
Now we compare this expression with the formula of depreciation.
= 24893
r = 12%
Therefore, Option (3) will be the answer.