Question

A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is

(a) 0.5 Wb
(b) 12.5 Wb
(c) zero
(d) 2 Wb​

Answer 1

Step-by-step explanation:

Magnetic flux = L I

= 5(2.5)

= 12.5 Wb

(b) 12.5 Wb

Answer 2

• Current=2.5A=I
• Inductance=B=5H

We know

`\boxed{\sf Magnetic\:flux=\O=BA}`

`\\ \qquad\quad\sf{:}\dashrightarrow \O=5(2.5)`

`\\ \qquad\quad\sf{:}\dashrightarrow \O=12.5Wb`