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Help on number 4

4.2 HW Straight Line Motion-Connecting Position, Velocity & Acceleration HW

Help on number 4 4.2 HW Straight Line Motion-Connecting Position, Velocity & Acceleration-example-1
User Illagrenan
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1 Answer

12 votes

Answer:

t=2s v(2)=-48feet/s

Step-by-step explanation:

-16t^2+16t+32=0

(t-2)(t+1)=0

t=2

v(t)=s'(t)=-32t+16

v(2)=s'(2)=-32*2+16=-48

User Sujey
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