Question

You push downward on a trunk at an angle 25° below the horizontal with a force of 500 N. If the trunk is on a flat surface and the coefficient of static friction is 0.61, what is the most massive trunk you will be able to move? [4 pts] for a Free Body Diagram correctly labeled​

Answer 1

The correct response is "54.19 kg".

Step-by-step explanation:

The given values are:

Force,

F = 500 N

Coefficient of static friction,

μ = 0.61

Angle,

`\Theta = 25^(\circ)`

As we know,

⇒
`F_x=F= \mu_s.N`

then,

⇒
`FCos \Theta=\mu_s(mg+FSin \Theta)`

On substituting the given values, we get

⇒
`500Cos(25^(\circ))=0.61[m(9.81)+500 Sin25^(\circ)]`

On substituting the values of Cos and Sin, we get

⇒
`453.154=0.61(9.81m+211.31)`

⇒
`453.154=5.9842m+128.8991`

⇒
`453.154-128.8991=5.9842m`

⇒
`324.2549=5.9842m`

⇒
`m=(324.2549)/(5.9842)`

⇒
`m=54.19 \ kg`