222k views
2 votes
At what value of x does the graph of the following function F(x) have a

vertical asymptote?

F(x)= 1/x+2

A. 2.
B. -2
C. -1
D. 0

User Miklosme
by
4.3k points

1 Answer

5 votes

Answer:

B

Explanation:

Given

f(x) =
(1)/(x+2)

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

User Chris Satchell
by
3.6k points