Question

During an experiment, the temperature of a mixture changes from 1214°F to 1535°F.

What is the percent of increase in the temperature of the mixture?

Enter your answer in the box as a percent rounded to the nearest hundredth. PLS HELP

Answer 1

• 27.35%

Explanation:

• Note the numbers should be 12 1/4 and 15 3/5

The change in temperature is

• 15 3/5 - 12 1/4 =
• 78/5 - 49/4 =
• 78*4/20 - 49*5/20 =
• 312/20 - 245/20 =
• 67/20

This change represents a percent increase

• 67/20 ÷ 245/20 × 100% =
• 67/245 × 100% =
• 27.35% (rounded)