Question

Find the equation of the line that

is perpendicular to the line y = 3x - 1
and
passes through the point (7.4).

Answer 1

Explanation:

The given line is

y = 3x - 1

3x - y - 1 = 0 .....i)

The line perpendicular to the line I Is

x + 3y + k = 0 .....ii)

The line II) passes through the point (7, 4) so

7 + 3 *4 + k = 0

7 + 12 + k = 0

19 + k = 0

I. e k = - 19

So the required equation is x + 3y - 19 = 0

Hope it will help :)❤