Question

Find 3 numbers in GP whose sum is 28 and product is 512​

Answer 1

4,8 and 16

Let the three numbers be a,ar, ar^2 ,

where r is the common ratio.

⇒a+ar+ar^2 =28 and a^3 r^3 =512

⇒ar=8⇒a+ar^2 =20

⇒8r^2 −20r+8=0

⇒r=2,r= 1/2

If r=2,a=4

Therefore, the three numbers are 4,8,16.

Explanation:

Hope it is helpful.....