Question

What is the equation in slope-intercept form of the line that crosses the x-axis at 36 and is perpendicular to the line represented by y=-x+5?​

Answer 1

y = x - 36

Explanation:

Here, we want to write an equation

Since it crosses the x-axis at x = 36; then (36,0) is a point on the line

for ;

y = -x + 5

if we compare this with the general form of;

y = mx + b

m = -1

If two lines are perpendicular, the product of their slopes = -1

Thus;

m1 * m2 = -1

-1 * m2 = -1

m2 = -1/-1

m2 = 1

The slope of the second line is 1

now, the equation in standard form is;

y = mx + c

m = 1

y = x + c

To get c, substitute the coordinates of the points that is on the line; (36,0)

0 = 36 + c

c = -36

so the equation of the line is;

y = x -36