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18 votes
18 votes
Find the slope of the line that passes through the points (0,-11) and (8,-8).

User AnthonyI
by
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2 Answers

16 votes
16 votes

Answer:

Explanation:

(x₁ ,y₁) = (0,-11) & (x₂ , y₂) = (8,-8)

Slope =
(y_(2)-y_(1))/(x_(2)-x_(1))\\


=(-8-[-11])/(8-0)\\\\=(-8+11)/(8)\\\\=(3)/(8)

17 votes
17 votes

To find the slope of a line, we can use the following formula:


\displaystyle \large{m = (y_2 - y_1)/(x_2 - x_1) }

m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:


\displaystyle \large{(x_1,y_1) = (0, - 11)} \\ \displaystyle \large{(x_2,y_2) = (8, - 8)}

Substitute the points in formula:


\displaystyle \large{m = ( - 8 -( - 11))/( 8 - 0) }

Negative multiply negative always come out as positive.


\displaystyle \large{m = ( - 8 + 11)/( 8 - 0) } \\ \displaystyle \large{m = ( 3)/( 8 ) } \\

Since m stands for slope, we can say that:


\displaystyle \large \boxed{ \tt{slope = (3)/(8) }}

User Ehsan Kia
by
2.7k points