Question

According to the Law of Conservation of Mass, how much water is produced if 22.5 g of

CHA react with 35.7g of Oz to form 48.9g of CO2?
CH4 + O2 + CO2 + H2O
o 107.1g
o 71.4g
o 62.1g
o 9.3g
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Ne

Answer 1

Answer: The amount of water produced is 9.3 grams

Step-by-step explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

`CH_4+2O_2\rightarrow CO_2+2H_2O`

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g + mass of water

48.9 g + mass of water = 58.2 g

mass of water = 9.3 g