Question

Is a=3 b=4 c=2 and d=-2 find the value of 3b²c-2ad
And ac-bd/7​

Answer 1

Explanation:

remember : calculations are usually done from left to right, but multiplications and divisions come before + and -.

and exponents come before multiplications and divisions.

and minus a negative number always turns into plus a positive number.

so,

3b²c - 2ad = 3×4²×2 - 2×3×-2 = 96 - -12 = 96 + 12 = 108

and

ac - bd/7 = 3×2 - 4×-2/7 = 6 - -8/7 = 6 + 8/7 = 7 1/7 ≈ 7.143

Answer 2

3b^2c-2ad=3*16*2-(2*3*-2)=108
ac-bd/7=3*2-(4*-2)/7=50/7 but if you mean (3*2-(4*-2))/7=2