Question

How do you solve this and method do you use?

Answer 1

Answer: B. 3x (1 - 3x²)

Explanation:

Given

`(9x^4-27x^6)/(3x^3)`

Factorize the numerator

=
`(3x^3*3x-3x^3*9x^3)/(3x^3)`

=
`(9x^4(3x-9x^3))/(3x^3)`

Cancel terms in numerator and denominator

=
`(3x(1-3x^2))/(1)`

=
`\boxed {3x(1-3x^2)}`

Hope this helps!! :)

Please let me know if you have any questions