Answer:
14units
Explanation:
Let the vertices of a rectangle be A(3, 1), B(3, 5), C(6, 5), and D(6, 1).
Using the formula for calculating distance between two points;
AB =√(5-1)²+(3-3)²
AB = √4²
AB = 4
BC = √(5-5)²+(6-3)²
BC = √3²
BC =>3
CD = √(1-5)²+(6-6)²
CD = √(-4)²
CD = √16
CD = 4
AD= √(1-1)²+(6-3)²
AD = √3²
AD = √9
AD =3
Perimeter of the rectangle = AB+BC+BD+AD
Perimeter of the rectangle = 4+3+4+3
Perimeter of the rectangle = 14units