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In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80. What ratio represents the cotangent of ∠G?

User Hanesjw
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1 Answer

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Given:

In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80.

To find:

The ratio which represents the cotangent of ∠G.

Solution:

In a right angle triangle, the ratio of the cotangent of an angle is


\cot \theta =(Base)/(Perpendicular)

It is also written as


\cot \theta =(Adjacent)/(Opposite)

In ΔFGH, the measure of ∠H=90°. So,


\cot G =(HG)/(FH)


\cot G =(80)/(39)

Therefore, the ratio for the cotangent of ∠G is
\cot G=(80)/(39).

User Harden
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