Question

Write the equation of the

line in slope intercept form
that contains the points
(-3,-2) and (-2,3).

Answer 1

y = 5x + 13

Explanation:

Slope = delta y/ delta x

(3-(-2))/(-2-(-3))

(5)/(1) = 5

Slope = 5

y = 5x + b

Find the y-intercept through substitution:

(-2,3)

3 = 5(-2) + b

3 = -10 + b

13 = b

Equation:

y = 5x + 13

Answer 2

y=5x+13

Explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-2))/(-2-(-3))

m=(3+2)/(-2+3)

m=5/1

m=5

y-y1=m(x-x1)

y-(-2)=5(x-(-3))

y+2=5(x+3)

y=5x+15-2

y=5x+13