Find the constant C such that x ^ 3 - 3x + 5 <= C where x in[0,3] 18 23 14 17 21

Steve Landey asked Mar 16, 2022

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Steve Landey asked Mar 16, 2022

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13 votes

Plug in maximum value of x (3) and see what you get. The maximum value of the expression when plugged in is C.

$3^3-3\cdot3+5=C$

$27-9+5=C\implies 23=C$

Now that means,

$x^3-3x+5\leq 23$ for any x in
[0,3]

Hope this helps :)

Adam Pope answered Mar 22, 2022

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