Question

Four processes p0,p1,p2,p3 with burst time as 3,4,2,1 respectively. Use first Come First served. Draw the Gantt chart

Answer 1

Please find the Gantt chart in the attachment file.

Step-by-step explanation:

Given:

`\to P_0 = 3\\\\\to P_1 = 4\\\\\to P_2 = 2\\\\\to P_3 = 1`

Calculating the average waiting time:

`\to(bust\ time)/( total\ process)`

`= (3+4+2+1)/(4)\\\\= (10)/(4)\\\\= 2.5`

And the chart is defined in the attached file please find it.