Question

4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cuál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?

Answer 1

a = 5 m / s² and x = 562.5 m

Step-by-step explanation:

Let's apply the kinematics relations

v = v₀ + at

v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

0 = v₀ - a t

a = v₀ / t

let's calculate

a = 75/15

a = 5 m / s²

let's look for the distance

0 = v₀² - 2a x

x = v₀² / 2a

let's calculate

x =
`(75^2)/(2 \ 5 )`

x = 562.5 m