Question

The spring in a dart gun has a force constant k of 200 N/m. If the spring is compressed 0.02 m prior to shooting the dart, how much kinetic energy will the spring impart to a dart

Answer 1

0.04 J

Step-by-step explanation:

Answer 2

Hi there!

Recall the equation for Spring Potential Energy:

`\large\boxed{PE = (1)/(2)kx^2}`

PE = Potential Energy (J)
k = Spring Constant (N/m)
x = displacement from equilibrium (m)

Plug in the givens:

`PE = (1)/(2)(200)(0.02^2) = 0.04 J`

All of the potential energy will be converted to kinetic energy when the spring is released, so:

`\large\boxed{KE = 0.04 J}`