Question

.The sum of two number is 40 when 13/4 multiplied by the larger number is subtracted from 11/2 multiplied by the smaller number. The difference is-25 Find the number ​

Answer 1

Explanation:

x + y = 40

x>y

(11/2)y - (13/4)*x = - 25

x = 40 - y

(11/2)y - (13/4)(40-y) = - 25 multiply by 4

22y - 13( 40 - y) = - 100

22y - 520 + 13y = -400 Add 520

35y = 120

y = 120 / 35

y = 3 3/7

x = 40 - y

x = 36 4/7