Question

A 7.0 kg box is at rest on a table. The static friction coefficient jis between the box and table is 0.40, and

the kinetic friction coefficient plx is 0.10. Then, a 25 N horizontal force is applied to the box.
What is the best estimate of the magnitude of the box's acceleration?
Round the answer (if non-zero) to two significant digits.
Choose 1 answer:
А
m
23
3.3
32
m
0.37

Answer 1

The best estimate for the magnitude of the box's acceleration is 3.6 m/s².

Step-by-step explanation:

The magnitude of the box's acceleration can be found using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the force is the applied force of 25 N, and the mass of the box is 7.0 kg. So, we have: F = m * a. Rearranging the equation to solve for acceleration, we get: a = F / m = 25 N / 7.0 kg = 3.6 m/s².