Question

A rectangle has a length two times the width. Describe how you would find the

perimeter and area.

Answer 1

Explanation:

L=2W

A=LW and since L=2W

A=2W^2

P=2(L+W), and again since L=2W

P=2(2W+W)

P=2(3W)

P=6W

Answer 2

perimeter = 6w

area = 2w^2

Explanation:

we can use the variable w for width, and 2w for length perimeter would be width + width + length + length, or 6w

area is width x length or 2w^2