Answer:
a) How long is the base of each parallelogram?
1 2/9 yards.
b) What is the area of the smallest rectangle of wall that the mirror could fit on?
3 Square yards
Explanation:
The parallelograms have a combined area of 3 1/7 square yards. The height of each parallelogram is 1 2/7 yards.
Step 1
We find the area of each of the parallelogram
This is calculated as:
Combined area of the parallelograms ÷ 2
= 3 1/7 square yards ÷ 2
= 22/7 square yards ÷ 2
= 22/7 square yards × 1/2
= 11/7 square yards
= 1 4/7 square yards.
Step 2
How long is the base of each parallelogram?
The height of each parallelogram is 1 2/7 yards.
Area of parallelogram = Base × Height
Base of each parallelogram = Area of each parallelogram/Height of each parallelogram
= 1 4/7 square yards ÷ 1 2/7 yards
= 11/7 square yards ÷ 9/7 yards
= 11/7 square yards × 7/9 yards
= 11/9 yards
= 1 2/9 yards.
Step 3
What is the area of the smallest rectangle of wall that the mirror could fit on?
Area of a rectangle = Length × Width
Length =(Base of parallelogram × 2)
Width = Base of parallelogram = 1 2/9 yards = 11/9 yards
Length = 1 2/9 yards × 2
= 11/9 × 2 = 22/9 yards
Area of rectangle = 11/9 × 22/9
= 242/81 square yards
= 2.987654321 square yards
Approximately = 3 Square yards