Please help me answer this question?

Gerard Banasig asked Apr 6, 2022

32,956 views

3 votes

Gerard Banasig asked Apr 6, 2022

2.9k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

27 votes

Answer:

P'(x)=2.2-0.12x

Explanation:

start by finding
P(x) = R(x)-C(x)

P(x)=3x-0.06x^2-286-0.8x

to find P'(x), you take the derivative of P(x)

P'(x)=(d)/(dx) (2.2x-286-0.06x^2)

(d)/(dx) (2.2x-286-0.06x^2)=2.2-0.12x

so
P'(x)=2.2-0.12x

Vance Lucas answered Apr 11, 2022

2.6k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers