Question

Enter the equation of the circle described below.

Center (3, -2), radius = 5

Answer 1

`(x-3)^(2) +(y+2)^(2) =5^(2)`

Explanation:

The equation of the circle with center A=(a,b) and radius = r are:

`(x-a)^(2)+(y-b)^(2) =r^(2)`

When A=(3,-2) and radius=r=-5

`(x-3)^(2) +(y+2)^(2) =5^(2)`