Question

Can u please help me with this question?

Answer 1

B)
`y=(-2)/(3)x-(-13)/(3)`

Explanation:

2x +3y = 5

3y = -2x + 5

Divide both sides by 3

`(3y)/(3)=(-2x)/(3)+(5)/(3)\\\\y =(-2)/(3)x+(5)/(3)`

Parallel lines have same slope.

m = (-2/3) ; (-2 , -3)

y - y1 = m(x -x1)

`y-[-3]=(-2)/(3)(x-[-2])\\\\y + 3 = (-2)/(3)(x +2)\\\\y + 3 =(-2)/(3)x + 2*(-2)/(3)\\\\y+3=(-2)/(3)x-(4)/(3)\\\\y=(-2)/(3)x-(4)/(3)-3\\\\y=(-2)/(3)x-(4)/(3)-(3*3)/(1*3)\\\\y=(-2)/(3)x-(4)/(3)-(9)/(3)\\\\y=(-2)/(3)x-(-13)/(3)`