Answer:
a
Explanation:
Given a tangent and a secant to a circle from an external point, then
The square of the tangent is equal to the product of the external part and the whole of the secant , that is
PB² = PA × PC = 4(4 + 32) = 4 × 36 = 144 ( take square root of both sides )
PB =
= 12 → a