Question

Find the equation of the line that is perpendicular to y=6x-2) and contains to the point (6-,2)

Answer 1

y = -1/6x - 1.

Explanation:

I am assuming that the point id (6, -2).

The slope of the required line = -1/6.

y - y1 = m(x - x1) where m = slope and x1,y1 is a point on the line so we have

y - (-2) = -1/6( x- 6)

y + 2 = -1/6x + 1

y = -1/6x - 1.