Question

Hi how was your day can you help please

Answer 1

Hi there!

`\huge\boxed{=27}`

`(3^(2)*(2^(3)+4))/(2^2)`

Use the order of operations to solve. Begin by evaluating the inside of the parenthesis.

Evalute 2³ = 8:

`(3^(2)*(8+4))/(2^2)`

Simplify:

`(3^(2)*(12))/(2^2)`

Evaluate each power. 3² = (3 × 3) = 9, and 2² = (2 × 2) = 4:

`(9*(12))/(4)`

Simplify:

`(108)/(4) = 27`