Question

A basketball is shot into the air. Its height is represented by the polynomial equation h(t) = –16t2 + 35t + 5, where h is the height of the basketball at t seconds. What's the height of the basketball at 1.5 seconds?

Question 4 options:

20.2 feet


18.8 feet


21.5 feet


16.7 feet

Answer 1

21.5 feet.

Explanation:

Let t = 1.5

`h(1.5)=-16(1.5)^2+35(1.5)+5\\h(1.5)=-36+52.5+5\\h(1.5)=21.5`

Therefore, at 1.5 seconds, the basketball is 21.5 feet in the air.

Answer 2

height = 21.5 ft

Explanation:

Substitute t = 1.5 into h(t) and evaluate

h(1.5) = - 16(1.5)² + 35(1.5) + 5

= - 16(2.25) + 52.5 + 5

= - 36 + 57.5

= 21.5 ft