Answer:
-x^2-2x-19
Explanation:
f(x)=(2x^2+3x-9) - g(x)=5x+11
First you must distribute the negative into g(x) so it would be g(x)=-5x-11
2x^2+3x-9-5x-11= 2x^2-2x-20
then you must add h(x) so...
2x^2-2x-20+(-3x^2+1)=
2x^2 + 3x - 9 is = (2x- 3)(x + 3)
5x + 11 is = 5x + 11 bc u cant factor it.
-3x^2 + 1 is = -3x^2 + 1 because it cant factor.
- g(x) + h(x) is = x(-g + h)
hope this helped lol
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