Question

How many atoms are in 1.4 moles of H3PO4?

8.4 X 10^23 atoms
8.9 X 10^23 atoms
8.4 X 10^23 grams
8.4 X 10^23 moles

Answer 1

8.4 × 10²³ atoms H₃PO₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Moles
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 1.4 \ mol \ H_3PO_4((6.022 \cdot 10^(23) \ atoms \ H_3PO_4)/(1 \ mol \ H_3PO_4))`
2. [DA] Multiply [Cancel out units]:
   `\displaystyle 8.4308 \cdot 10^(23) \ atoms \ H_3PO_4`

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄