Question 1

Look at this cone:

,,

Question 2

We know

$\boxed{\sf \star TSA_((Cone))=\pi r(r+\ell)}$

$\\ \sf\longmapsto TSA_((Old\:Cone))=2</p><p> (22)/(7)* 2(2+3)$

$\\ \sf\longmapsto TSA_((Old\:Cone))=(44)/(7)(5)$

$\\ \sf\longmapsto TSA_((Old\:Cone))=(220)/(7)$

$\\ \sf\longmapsto TSA_((Old\:Cone))=31.4ft^2$

Now

$\\ \sf\longmapsto TSA_((New\:Cone))=(22)/(7)* 4(4+6)$

$\\ \sf\longmapsto TSA_((New\:Cone))=(88)/(7)(10)$

$\\ \sf\longmapsto TSA_((New\:Cone))=(880)/(7)$

$\\ \sf\longmapsto TSA_((New\:Cone))=125.7cm^2$

So

$\\ \sf\longmapsto (TSA_((New\:Cone)))/(TSA_((Old\:Cone)))=(125.7)/(31.4)$

$\\ \sf\longmapsto (TSA_((New\:Cone)))/(TSA_((Old\:Cone)))=(4)/(1)$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_((New\:Cone))}:{TSA_((Old\:Cone))}=4:1}}}$

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