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Indicate all possible values for the variable in each of the expressions: sqrt(2x+2)+sqrt(6-4x)

User Nishant Pardamwar
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Answer:

Given expression:


  • √(2x+2)+√(6-4x)

The first root is valid when:

  • 2x + 2 ≥ 0 ⇒ 2x ≥ - 2 ⇒ x ≥ - 1

The second root is valid when:

  • 6 - 4x ≥ 0 ⇒ 4x ≤ 6 ⇒ x ≤ 1.5

So the variable x can get values within interval:

  • -1 ≤ x ≤ 1.5 or
  • x = [-1, 1.5]
User Yoshimi
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